作业2（4）求m和n之间的和

#include <stdio.h> /*饶了我吧*/
int main(void)
{         
    int i, m, n;     
    double sum;      
    scanf_s("%d",&m);
    scanf_s("%d",&n);
    sum = 0;            
    for(i = m; i <= n; i++)          /*计算nm之间的数*/ 
        sum = sum + i * i + 1.0 / i;       
    printf("sum = %.6f\n", sum);  
    
    
    return 0; 
}