Java实现十进制的整数转为二进制的字符串

1.描述：输入一个十进制的整数，返回该整数对应二进制数的字符串

2.JDK的实现（java.lang.Integer#toBinaryString）

　　public static String toBinaryString(int i) {
        return toUnsignedString0(i, 1);
   }

    /**
     * Convert the integer to an unsigned number.
     */
    private static String toUnsignedString0(int val, int shift) {
        // assert shift > 0 && shift <=5 : "Illegal shift value";
        int mag = Integer.SIZE - Integer.numberOfLeadingZeros(val);
        int chars = Math.max(((mag + (shift - 1)) / shift), 1);
        char[] buf = new char[chars];

        formatUnsignedInt(val, shift, buf, 0, chars);

        // Use special constructor which takes over "buf".
        return new String(buf, true);
    }

    /**
     * Format a long (treated as unsigned) into a character buffer.
     * @param val the unsigned int to format
     * @param shift the log2 of the base to format in (4 for hex, 3 for octal, 1 for binary)
     * @param buf the character buffer to write to
     * @param offset the offset in the destination buffer to start at
     * @param len the number of characters to write
     * @return the lowest character  location used
     */
     static int formatUnsignedInt(int val, int shift, char[] buf, int offset, int len) {
        int charPos = len;
        int radix = 1 << shift;
        int mask = radix - 1;
        do {
            buf[offset + --charPos] = Integer.digits[val & mask];
            val >>>= shift;
        } while (val != 0 && charPos > 0);

        return charPos;
    }

    final static char [] DigitTens = {
        '0', '0', '0', '0', '0', '0', '0', '0', '0', '0',
        '1', '1', '1', '1', '1', '1', '1', '1', '1', '1',
        '2', '2', '2', '2', '2', '2', '2', '2', '2', '2',
        '3', '3', '3', '3', '3', '3', '3', '3', '3', '3',
        '4', '4', '4', '4', '4', '4', '4', '4', '4', '4',
        '5', '5', '5', '5', '5', '5', '5', '5', '5', '5',
        '6', '6', '6', '6', '6', '6', '6', '6', '6', '6',
        '7', '7', '7', '7', '7', '7', '7', '7', '7', '7',
        '8', '8', '8', '8', '8', '8', '8', '8', '8', '8',
        '9', '9', '9', '9', '9', '9', '9', '9', '9', '9',
        } ;

 

3.自定义实现

 

public static String toBinaryString(Integer number) {
        StringBuilder sb = new StringBuilder();
        for (int n = number; n > 0 ; n /= 2) {
            sb.append(n %  2);
        }
        return sb.toString();
    }