HasMany() = (1..*) HasOptional() = (1..0,1) HasRequired() = (1..1)

http://www.cnblogs.com/yeagen/archive/2012/10/15/2724237.html

posted @ 2016-12-30 16:17  AnswerCard  阅读(187)  评论(0编辑  收藏  举报