Codeforces 946 B.Weird Subtraction Process

 

B. Weird Subtraction Process
 
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

You have two variables a and b. Consider the following sequence of actions performed with these variables:

  1. If a = 0 or b = 0, end the process. Otherwise, go to step 2;
  2. If a ≥ 2·b, then set the value of a to a - 2·b, and repeat step 1. Otherwise, go to step 3;
  3. If b ≥ 2·a, then set the value of b to b - 2·a, and repeat step 1. Otherwise, end the process.

Initially the values of a and b are positive integers, and so the process will be finite.

You have to determine the values of a and b after the process ends.

Input

The only line of the input contains two integers n and m (1 ≤ n, m ≤ 1018). n is the initial value of variable a, and m is the initial value of variable b.

Output

Print two integers — the values of a and b after the end of the process.

Examples
input
Copy
12 5
output
0 1
input
Copy
31 12
output
7 12
Note

Explanations to the samples:

  1. a = 12, b = 5  a = 2, b = 5  a = 2, b = 1  a = 0, b = 1;
  2. a = 31, b = 12  a = 7, b = 12.

 

 

代码:

 1 #include<iostream>
 2 #include<cstring>
 3 #include<cstdio>
 4 #include<cmath>
 5 #include<algorithm>
 6 #include<cstdlib>
 7 using namespace std;
 8 typedef long long ll;
 9 const int maxn=1e5+10;
10 #define ios ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
11 int main(){
12     ll a,b;
13     ios;
14     cin>>a>>b;
15     while(1){
16         if(a==0||b==0) break;
17         if(a>=2*b){
18             a=a%(2*b);
19         }
20         else if(b>=2*a){
21             b=b%(2*a);
22         }
23         else break;
24     }
25     cout<<a<<" "<<b<<endl;
26 }

 

posted @ 2018-03-08 20:16  ZERO-  阅读(296)  评论(0编辑  收藏  举报