Sql快速查看表结构

Sql数据库使用语句快速查看表结构

 

--快速查看表结构  
SELECT  CASE WHEN col.colorder = 1 THEN obj.name  
                 ELSE ''  
            END AS 表名,  
        col.colorder AS 序号 ,  
        col.name AS 列名 ,  
        ISNULL(ep.[value], '') AS 列说明 ,  
        t.name AS 数据类型 ,  
        col.length AS 长度 ,  
       ISNULL(COLUMNPROPERTY(col.id, col.name, 'Scale'), 0) AS 小数位数 ,  
        CASE WHEN COLUMNPROPERTY(col.id, col.name, 'IsIdentity') = 1 THEN ''  
            ELSE ''  
        END AS 标识 ,  
       CASE WHEN EXISTS ( SELECT   1  
                           FROM     dbo.sysindexes si  
                                    INNER JOIN dbo.sysindexkeys sik ON si.id = sik.id  
                                                              AND si.indid = sik.indid  
                                    INNER JOIN dbo.syscolumns sc ON sc.id = sik.id  
                                                            AND sc.colid = sik.colid  
                                   INNER JOIN dbo.sysobjects so ON so.name = si.name  
                                                              AND so.xtype = 'PK'  
                         WHERE    sc.id = col.id  
                                   AND sc.colid = col.colid ) THEN ''  
             ELSE ''  
        END AS 主键 ,  
        CASE WHEN col.isnullable = 1 THEN ''  
            ELSE ''  
        END AS 允许空 ,  
        ISNULL(comm.text, '') AS 默认值  
FROM    dbo.syscolumns col  
        LEFT  JOIN dbo.systypes t ON col.xtype = t.xusertype  
        inner JOIN dbo.sysobjects obj ON col.id = obj.id  
                                         AND obj.xtype = 'U'  
                                         AND obj.status >= 0  
        LEFT  JOIN dbo.syscomments comm ON col.cdefault = comm.id  
        LEFT  JOIN sys.extended_properties ep ON col.id = ep.major_id  
                                                    AND col.colid = ep.minor_id  
                                                      AND ep.name = 'MS_Description'  
        LEFT  JOIN sys.extended_properties epTwo ON obj.id = epTwo.major_id  
                                                         AND epTwo.minor_id = 0  
                                                        AND epTwo.name = 'MS_Description'  
WHERE   obj.name like '%e%' --表名  
ORDER BY col.colorder ;  

 

posted on 2016-07-11 13:39  Trafalgar  阅读(613)  评论(0编辑  收藏  举报

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