Java——hashSet集合去重分析

一、hashSet集合去重:

  1)通过hashCodeequals两方法保证数据的唯一性;

  2)如果hashCode相同才判断元素的equals

二、代码:

   1、实体类:重写hashCode和equals方法;

public class Person {
    private String name;
    private int age;
    Person(String name,int age){
        this.name=name;
        this.age=age;
    }
    public String getName(){
        return name;
    }
    public int getAge(){
        return age;
    }
    //重写hashCode方法
    public int hashCode(){
        System.out.println(this.name+".....hashCode");
        return this.name.hashCode()+this.age;
    }
    //重写equals方法
    public boolean equals(Object obj){
        if (!(obj instanceof Person)) return false;
        Person p=(Person)obj;
        System.out.println(this.name+"..equals.."+p.name);
        return this.name.equals(p.name) && this.age==p.age;
    }
}

 

  2、测试类:

public class Test {
    public static void main(String[] args) {
        HashSet hs=new HashSet();
        hs.add(new Person("zs0",0));
        hs.add(new Person("zs1",1));
        hs.add(new Person("zs1",1));
        hs.add(new Person("zs2",2));

        for ( Iterator it=hs.iterator();it.hasNext();){
            Person p=(Person)it.next();
            System.out.println(p.getName()+"....."+p.getAge());
        }
    }
}

 

posted @ 2019-07-24 16:01  开拖拉机的拉风少年  阅读(679)  评论(0编辑  收藏  举报