hdu 6092 Rikka with Subset（多重背包）

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=6092

 

#include <cstdio>
#include <iostream>
#include <cstring>
using namespace std;
const int maxn = 1e4 + 5;
int b[maxn] , dp[maxn] , n , m;
int main() {
    int t;
    scanf("%d", &t);
    while(t--) {
        scanf("%d%d" , &n , &m);
        for (int i = 0; i <= m; i++) {
            scanf("%d" , &b[i]);
            dp[i] = 0;
        }
        dp[0] = 1;
        int count = 0;
        for (int i = 1; i <= m; i++) {
            while (dp[i] < b[i]) {
                count++;
                if(count != n) printf("%d " , i);
                else printf("%d\n" , i);
                for (int j = m ; j >= i ; j--) {
                    dp[j] += dp[j - i];
                }
            }
        }
    }
    return 0;
}

 

题解：就是一道多重背包，每次有优先拿最小的来更新看代码就很好理解了。