位域中位的顺序

在AIX主机上编译运行以下程序:

 1 #include <iostream>
 2 
 3 typedef struct
 4 {
 5     unsigned int b1 : 1;
 6     unsigned int b2 : 1;
 7     unsigned int b3 : 1;
 8     unsigned int b4 : 1;
 9     unsigned int b5 : 1;
10     unsigned int b6 : 1;
11     unsigned int b7 : 1;
12     unsigned int b8 : 1;
13 } bit8;
14 
15 typedef union
16 {
17     bit8 bType;
18     char cType;
19 } byte;
20 
21 int main( void )
22 {
23     byte chTest;
24     chTest.cType = '1';
25     
26     std::cout << chTest.bType.b1 << " ";
27     std::cout << chTest.bType.b2 << " ";
28     std::cout << chTest.bType.b3 << " ";
29     std::cout << chTest.bType.b4 << " ";
30     std::cout << chTest.bType.b5 << " ";
31     std::cout << chTest.bType.b6 << " ";
32     std::cout << chTest.bType.b7 << " ";
33     std::cout << chTest.bType.b8 << std::endl;
34 
35     return 0;
36 }

运行结果为:

0 0 1 1 0 0 0 1

但是同样的程序,在 Linux 主机上的运行结果却为:

1 0 0 0 1 1 0 0

位域也分大端序和小端序的吗?

 

位域的类型使用 int 而不是 unsigned int 的时候,Linux主机输出的是 -1 而不是 1

 

posted @ 2014-12-15 15:11  StupidTortoise  阅读(653)  评论(0编辑  收藏  举报