KMP POJ 2752 Seek the Name, Seek the Fame

 

题目传送门

 1 /*
 2     题意：求出一个串的前缀与后缀相同的字串的长度
 3     KMP：nex[]就有这样的性质，倒过来输出就行了
 4 */
 5 /************************************************
 6 * Author        :Running_Time
 7 * Created Time  :2015-8-10 11:29:25
 8 * File Name     :POJ_2752.cpp
 9  ************************************************/
10 
11 #include <cstdio>
12 #include <algorithm>
13 #include <iostream>
14 #include <sstream>
15 #include <cstring>
16 #include <cmath>
17 #include <string>
18 #include <vector>
19 #include <queue>
20 #include <deque>
21 #include <stack>
22 #include <list>
23 #include <map>
24 #include <set>
25 #include <bitset>
26 #include <cstdlib>
27 #include <ctime>
28 using namespace std;
29 
30 #define lson l, mid, rt << 1
31 #define rson mid + 1, r, rt << 1 | 1
32 typedef long long ll;
33 const int MAXN = 4e5 + 10;
34 const int INF = 0x3f3f3f3f;
35 const int MOD = 1e9 + 7;
36 int nex[MAXN];
37 char str[MAXN];
38 
39 void get_nex(void)  {
40     int len = strlen (str);
41     int i = 0, j = -1;  nex[0] = -1;
42     while (i < len) {
43         if (j == -1 || str[j] == str[i])    {
44             j++;    i++;    nex[i] = j;
45         }
46         else    j = nex[j];
47     }
48     vector<int> ans;
49     while (i != -1) {
50         ans.push_back (i);  i = nex[i];
51     }
52     for (int i=ans.size ()-2; i>=0; --i)    {
53         printf ("%d ", ans[i]);
54     }
55     puts ("");
56 }
57 
58 int main(void)    {     //POJ 2752 Seek the Name, Seek the Fame
59     while (scanf ("%s", str) == 1)  {
60         get_nex ();
61     }
62 
63     return 0;
64 }

 

posted @ 2015-08-10 13:39  Running_Time  阅读(204)  评论(0)  编辑  收藏  举报