统计任意两个正整数之间所有奇数的和
题目来源: Conditions and Loops
1 #!/usr/bin/python3
2 # sum all odds between two positive integer
3
4 a = int(input("Please input one positive integer > ")) # in python3, input() replace of raw_input(), so use int()
5 b = int(input("Please input another positive integer > "))
6
7 if a == b: # use condition check
8 print("please input two different integer")
9 exit() # should add it, elsewise it will continue execute the print() statement in the end
10 elif a > b:
11 small_num = b
12 large_num = a
13 else:
14 small_num = a
15 large_num = b
16
17 sum_odd = 0
18 for i in range(small_num, large_num + 1): # use for loop, and use range() function
19 if i % 2 == 1:
20 sum_odd = sum_odd + i
21
22 print("the sum of all odds number between " + str(small_num) + " and " + str(large_num) + " is " + str(sum_odd))
运行结果：
ubuntu:~/python3$ python3 sum_odd.py Please input one positive integer > 100 Please input another positive integer > 200 the sum of all odds number between 100 and 200 is 7500
虽然真的很简单，但是挺有意思的，而且也能体现 python 这个语言的语法的确比较简洁，很直观。
