生成简单的Makefile文件(Python实现)

在linux下写几个测试程序,还要一行行的输入g++命令进行编译,当经常改测试代码的时候,那一次次的敲(或者一次次的上线箭头选)也感觉不爽,不如make来的快。用Makefile的好处就不用多说了,这里我写了个脚本,其功能是自动搜索当前目录(不包括子目录)下的“.c”文件生成Makefile文件。
代码在这里,功能有限(适用于单个文件是一个独立的测试代码的情况),需要的朋友可以稍作修改以满足需求。

 1 #! /usr/bin/python
2 '''
3 File : genMakefile.py
4 Author : Mike
5 E-Mail : Mike_Zhang@live.com
6 '''
7 import os
8
9 def genMakefileStr(dir,surfix = '.c'):
10 msg = ''
11 msg = msg + 'CC = gcc' + '\n'
12 msg = msg + 'CFLAGS = -g -O2 -Wall' + '\n\n'
13
14 fList = []
15 for dirPath,dirNames,fileNames in os.walk(dir):
16 for file in fileNames:
17 name,extension = os.path.splitext(file)
18 if extension == surfix:
19 fList.append(name)
20 break # only search the current directory
21 str1 = 'all:\n'
22 str2 = ''
23 str3 = 'clean:\n'
24 for f in fList:
25 str1 = str1 + '\tmake ' + f + '\n'
26 str2 = ('%s%s:%s.o\n') % (str2,f,f)
27 str2 = ('%s\t$(CC) -o %s %s.o\n\n') % (str2,f,f)
28 str3 = ('%s\trm -f %s\n') % (str3,f)
29 str3 = str3 + '\trm -f *.o\n'
30 strClean = '.c.o:\n\t$(CC) $(CFLAGS) -c -o $*.o $<\n'
31 msg = ('%s%s\n%s\n%s\n%s') % (msg,str1,str2,str3,strClean)
32 #print 'msg : \n'
33 #print msg
34 return msg
35
36 if __name__ == '__main__':
37 str = genMakefileStr('.','.c')
38 file = open("Makefile","w")
39 file.write(str)
40 file.close()
41 print str

运行效果如下(示例):

 1 # ./genMakefile.py          
2 CC = gcc
3 CFLAGS = -g -O2 -Wall
4
5 all:
6 make pfun1
7 make pfun2
8
9 pfun1:pfun1.o
10 $(CC) -o pfun1 pfun1.o
11
12 pfun2:pfun2.o
13 $(CC) -o pfun2 pfun2.o
14
15
16 clean:
17 rm -f pfun1
18 rm -f pfun2
19 rm -f *.o
20
21 .c.o:
22 $(CC) $(CFLAGS) -c -o $*.o $<

运行脚本后进行make即可。

附:

感觉上面的那个脚本用着不方便,随后修改修改,代码如下:

#! /usr/bin/python
'''
  File      : genMakefile.py
  Author    : Mike
  E-Mail    : Mike_Zhang@live.com
'''
import os,sys
 
surfix = ['.c','.cpp']

def genMakefileStr(dir):
    msg = ''
    msg = msg + 'CC = g++ ' + '\n'
    msg = msg +  'CFLAGS = -g -O2 -Wall' + '\n\n'
    
    fList = []
    for dirPath,dirNames,fileNames in os.walk(dir):
        for file in fileNames:
            name,extension = os.path.splitext(file)
            if surfix.count(extension) > 0:
                fList.append(name)
        break # only search the current directory
    str1 = 'all:\n'
    str2 = ''
    str3 = 'clean:\n'
    for f in fList:
        str1 = str1 + '\tmake ' + f + '\n'
        str2 = ('%s%s:%s.o\n') % (str2,f,f)
        str2 = ('%s\t$(CC) -o %s %s.o\n\n') % (str2,f,f)
        str3 = ('%s\trm -f %s\n') % (str3,f)
    str3 = str3 + '\trm -f *.o\n'
    strClean = '.c.cpp.o:\n\t$(CC) $(CFLAGS) -c -o $*.o $<\n'
    msg = ('%s%s\n%s\n%s\n%s') % (msg,str1,str2,str3,strClean) 
    #print 'msg : \n'
    #print msg
    return msg
 
if __name__ == '__main__':
    for arg in sys.argv[1:]:
        print arg
    str = genMakefileStr(arg)
    if arg[-1] == '/':arg = arg[:-1]
    file = open(arg+"/Makefile","w")
    file.write(str)
    file.close()
    print str

把文件genMakefile.py改名为genMakefile,复制到/usr/local/bin下,以后在需要的目录里面执行如下命令即可:

genMakefile .

本文github地址:

https://github.com/mike-zhang/mikeBlogEssays/blob/master/2011/生成简单的Makefile文件(Python实现).txt

欢迎补充 

posted on 2012-01-17 13:53  Mike_Zhang  阅读(6617)  评论(2编辑  收藏  举报