HDU 2057
A + B Again
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11594 Accepted Submission(s): 5049
Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !
Input
The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.
Output
For each test case,print the sum of A and B in hexadecimal in one line.
Sample Input
+A -A +1A 12 1A -9 -1A -12 1A -AA
Sample Output
0 2C 11 -2C -90
也就是十六进制的运算而已,读懂题目就可以直接做了
#include<stdio.h> int main() { __int64 a,b,ans; while(scanf("%I64X%I64X",&a,&b)!=EOF) { ans=a+b; if(ans<0) { printf("-"); ans=-ans; } printf("%I64X\n",ans); } return 0; }