PHP - 防止 XSS(跨站脚本攻击)
<?PHP /** * @blog http://www.phpddt.com * @param $string * @param $low 安全别级低 */ function clean_xss(&$string, $low = False) { if (! is_array ( $string )) { $string = trim ( $string ); $string = strip_tags ( $string ); $string = htmlspecialchars ( $string ); if ($low) { return True; } $string = str_replace ( array ('"', "\\", "'", "/", "..", "../", "./", "//" ), '', $string ); $no = '/%0[0-8bcef]/'; $string = preg_replace ( $no, '', $string ); $no = '/%1[0-9a-f]/'; $string = preg_replace ( $no, '', $string ); $no = '/[\x00-\x08\x0B\x0C\x0E-\x1F\x7F]+/S'; $string = preg_replace ( $no, '', $string ); return True; } $keys = array_keys ( $string ); foreach ( $keys as $key ) { clean_xss ( $string [$key] ); } } //just a test $str = "<script>alert(document.cookie)</script>"; clean_xss($str); //如果你把这个注释掉,你就知道xss攻击的厉害了 echo $str; ?>
posted on 2016-01-17 18:07 ultrastrong 阅读(2008) 评论(0) 编辑 收藏 举报