剑指Offer28 最小的K个数(Partition函数应用+大顶堆)
包含了Partition函数的多种用法
以及大顶堆操作
1 /************************************************************************* 2 > File Name: 28_KLeastNumbers.cpp 3 > Author: Juntaran 4 > Mail: JuntaranMail@gmail.com 5 > Created Time: 2016年08月31日 星期三 19时45分41秒 6 ************************************************************************/ 7 8 #include <stdio.h> 9 #include <bits/stdc++.h> 10 11 using namespace std; 12 13 14 // 大顶堆求最小K个数 15 typedef multiset<int, greater<int> > intSet; 16 typedef multiset<int, greater<int> >::iterator setIterator; 17 18 void GetKLeastNumbers2(int* data, intSet& leastNumbers, int length, int k) 19 { 20 leastNumbers.clear(); 21 22 if (k<1 || length<k) 23 return; 24 25 for (int i = 0; i < length; ++i) 26 { 27 if (leastNumbers.size() < k) 28 leastNumbers.insert(data[i]); 29 30 else 31 { 32 setIterator Greatest = leastNumbers.begin(); 33 if (data[i] < *(leastNumbers.begin())) 34 { 35 leastNumbers.erase(Greatest); 36 leastNumbers.insert(data[i]); 37 } 38 } 39 } 40 41 for (setIterator iter = leastNumbers.begin(); iter != leastNumbers.end(); ++iter) 42 { 43 printf("%d ", *iter); 44 } 45 printf("\n"); 46 } 47 48 49 void swap(int* p, int* q) 50 { 51 int temp = *p; 52 *p = *q; 53 *q = temp; 54 } 55 56 // Partition函数应用 57 int Partition(int* data, int length, int start, int end) 58 { 59 if (data==NULL || length<=0 || start<0 || end>=length) 60 return -1; 61 62 // 令数组第一个数字为标杆 63 int index = start; 64 65 // 标杆与数组最后一个元素交换 66 swap(&data[index], &data[end]); 67 68 int small = start - 1; 69 for (index = start; index < end; ++index) 70 { 71 if (data[index] < data[end]) 72 { 73 ++ small; 74 if (small != index) 75 { 76 swap(&data[index], &data[small]); 77 } 78 } 79 } 80 ++ small; 81 swap(&data[small], &data[end]); 82 83 return small; 84 } 85 86 // 利用Partiton实现快排 87 void quickSort(int* data, int length, int start, int end) 88 { 89 if (start==end || data==NULL || length<=0) 90 return; 91 92 int index = Partition(data, length, start, end); 93 // printf("index is %d\n", index); 94 if (index > start) 95 quickSort(data, length, start, index-1); 96 if (index < end) 97 quickSort(data, length, index+1, end); 98 } 99 100 // 利用Partition寻找出现次数超过一半的数 (中位数) 101 int GetMoreThanHalf(int* input, int length) 102 { 103 if (input==NULL || length<=0) 104 return -1; 105 int start = 0; 106 int end = length - 1; 107 int index = Partition(input, length, start, end); 108 int middle = length >> 1; 109 while (index != middle) 110 { 111 if (index > middle) 112 { 113 end = index - 1; 114 index = Partition(input, length, start, end); 115 } 116 else 117 { 118 start = index + 1; 119 index = Partition(input, length, start, end); 120 } 121 } 122 int ret = input[middle]; 123 // 检验是否正确 124 int count2 = 0; 125 for (int i = 0; i < length; ++i) 126 { 127 if (input[i] == ret) 128 count2 ++; 129 } 130 if (count2*2 > length) 131 { 132 printf("middle number is %d\n", input[middle]); 133 return ret; 134 } 135 else 136 { 137 printf("Not Find\n"); 138 return -1; 139 } 140 } 141 142 143 // 利用Partition寻找第K小的数 144 int GetKthNumber(int* input, int length, int k) 145 { 146 if (input==NULL || length<=0 || k<=0 || k>length) 147 return -1; 148 int start = 0; 149 int end = length - 1; 150 int index = Partition(input, length, start, end); 151 while (index != k - 1) 152 { 153 if (index > k-1) 154 { 155 end = index-1; 156 index = Partition(input, length, start, end); 157 } 158 else 159 { 160 start = index + 1; 161 index = Partition(input, length, start, end); 162 } 163 } 164 printf("Kth is %d\n", input[index]); 165 return input[index]; 166 } 167 168 169 // 利用Partition寻找最小K个数 170 void GetKLeastNumbers(int* input, int length, int* output, int k) 171 { 172 if (input==NULL || output==NULL || length<=0 || k<=0 || k>length) 173 { 174 return; 175 } 176 int start = 0; 177 int end = length - 1; 178 int index = Partition(input, length, start, end); 179 while (index != k - 1) 180 { 181 if (index > k-1) 182 { 183 end = index - 1; 184 index = Partition(input, length, start, end); 185 } 186 else 187 { 188 start = index + 1; 189 index = Partition(input, length, start, end); 190 } 191 // printf("index is %d\n", index); 192 } 193 for (int i = 0; i < k; ++i) 194 output[i] = input[i]; 195 196 for (int i = 0; i < k; ++i) 197 printf("%d ", output[i]); 198 printf("\n"); 199 } 200 201 202 int main() 203 { 204 int k = 5; 205 int nums[] = {3,5,5,5,6,5,7,1,2,9}; 206 int length = 10; 207 int output[k] = {0}; 208 209 // 快速排序 210 quickSort(nums, length, 0, length-1); 211 for (int i = 0; i < length; ++i) 212 printf("%d ", nums[i]); 213 printf("\n"); 214 215 // 求最小K个数 216 GetKLeastNumbers(nums, length, output, k); 217 218 // 求第K大的数 219 GetKthNumber(nums, length, k); 220 221 // 求数组中超过一半的数(中位数) 222 GetMoreThanHalf(nums, length); 223 224 // 大顶堆求最小K个数 225 intSet leastNumbers; 226 GetKLeastNumbers2(nums, leastNumbers, length, k); 227 }