sicily 1063. Who's the Boss 排序+递推

 1 #include <cstdio>
 2 #include <algorithm>
 3 using namespace std;
 4 struct Emp{
 5     int id, salary, height, boss, sub;
 6     Emp(int i=0, int s=0, int h=0, int b=0, int sb=0) : 
 7             id(i), salary(s), height(h), boss(b), sub(sb) {}
 8 } emp[30000];
 9 bool cmp(Emp a, Emp b) {
10     return a.salary < b.salary;
11 }
12 int main() {
13     int t;
14     scanf("%d", &t);
15     while (t--) {
16         int m, q;
17         scanf("%d%d", &m, &q);
18         for (int i = 0; i < m; i++) {
19             int id, sal, hei;
20             scanf("%d%d%d", &id, &sal, &hei);
21             emp[i] = Emp(id, sal, hei); // Boss id 与 subordinate 默认为 0 
22         }
23         // 按薪水升序排序 
24         sort(emp, emp+m, cmp);
25         // 找直属上司,计算下属数量 
26         for (int i = 0; i < m-1; i++) {
27             // 直属上司在数组中对应的下标 boss 
28             int boss = -1;
29             for (int j = i+1; j < m; j++)
30               if (emp[j].height >= emp[i].height) {
31                   boss = j;
32                   break;
33               }
34             if (boss != -1) {
35                 emp[i].boss = emp[boss].id;
36                 emp[boss].sub += emp[i].sub + 1;
37             }
38         }
39         for (int i = 0; i < q; i++) {
40             int query;
41             scanf("%d", &query);
42             int j, index = m-1;
43             for (j = 0; j < m; j++)  // 找到要查询的对象对应的下标 index 
44                 if (emp[j].id == query) {
45                     index = j;
46                     break;
47                 }
48             printf("%d %d\n", emp[index].boss, emp[index].sub);
49         }
50     }
51 }

 

posted on 2015-11-13 11:12  松下风  阅读(128)  评论(0编辑  收藏  举报

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