图的存储结构(Java)

 1 //1 无向图的邻接矩阵实现 时间复杂度:O(n^2) 空间复杂度:O(n^2)
 2 class Graph
 3 {
 4     public int[][] adjacencyMatrix;  //邻接矩阵
 5     public int vexnum;  //边数
 6     public int arcnum;  //顶点数
 7     public char[] vexs;  //顶点数组
 8     
 9     public Graph(int vexnum, int arcnum)
10     {
11         this.vexnum = vexnum;
12         this.arcnum = arcnum;
13         this.adjacencyMatrix = new int[vexnum][vexnum];
14         this.vexs = new char[vexnum];
15     }
16     
17     public void createUDG()  
18     {
19         //1 创建顶点数组
20         Scanner input = new Scanner(System.in);
21         for(int i = 0; i < this.vexnum; i++)
22             this.vexs[i] = input.next().charAt(0);
23         
24         //2 初始化邻接矩阵
25         for(int j = 0; j < this.vexnum; j++)
26             for(int k = 0; k < this.vexnum; k++)
27                 this.adjacencyMatrix[j][k] = 0;
28         
29         //3 根据顶点创建邻接矩阵
30         for(int p = 0; p < this.arcnum; p++)
31         {
32             char a = input.next().charAt(0);
33             char b = input.next().charAt(0);
34             int i = this.locateVex(a);
35             int j = this.locateVex(b);
36             this.adjacencyMatrix[i][j] = this.adjacencyMatrix[j][i] = 1; //对称阵
37         }
38     }
39     
40     public int locateVex(char vex)
41     {
42         int i;
43         for(i = 0; i < this.vexs.length && vex != this.vexs[i]; i++);
44         return i;
45     }
46 }
47 
48 //2 有向图的邻接矩阵实现 时间复杂度:O(n^2) 空间复杂度:O(n^2)
49 class Graph  
50 {
51     public int[][] adjacencyMatrix;
52     public int vexnum;
53     public int arcnum;
54     public char[] vexs;
55     
56     public Graph(int vexnum, int arcnum)
57     {
58         this.vexnum = vexnum;
59         this.arcnum = arcnum;
60         this.adjacencyMatrix = new int[vexnum][vexnum];
61         this.vexs = new char[vexnum];
62     }
63     
64     public void createDG()
65     {
66         Scanner input = new Scanner(System.in);
67         for(int i = 0; i < this.vexnum; i++)
68             this.vexs[i] = input.next().charAt(0);
69         for(int j = 0; j < this.vexnum; j++)
70             for(int k = 0; k < this.vexnum; k++)
71                 this.adjacencyMatrix[j][k] = 0;
72         for(int p = 0; p < this.arcnum; p++)
73         {
74             char a = input.next().charAt(0);
75             char b = input.next().charAt(0);
76             int i = this.locateVex(a);
77             int j = this.locateVex(b);
78             this.adjacencyMatrix[i][j] = 1;
79         }
80     }
81     
82     public int locateVex(char vex)
83     {
84         int i;
85         for(i = 0; i < this.vexs.length && vex != this.vexs[i]; i++);
86         return i;
87     }
88 }

 

  1 //1 无向图的邻接表实现 时间复杂度: O(n+e) 空间复杂度: O(n+e)
  2 class ArcNode  //边结点
  3 {
  4     //public int info;
  5     public int adjvex;
  6     public ArcNode nextarc;
  7     
  8     public ArcNode(int adjvex)
  9     {
 10         this.adjvex = adjvex;
 11         this.nextarc = null;
 12     }
 13 }
 14 
 15 class VexNode  //顶点结点
 16 {
 17     public char data;
 18     public ArcNode firstarc;
 19     
 20     public VexNode(char data)
 21     {
 22         this.data = data;
 23         this.firstarc = null;
 24     }
 25 }
 26 
 27 class Graph 
 28 {
 29     public VexNode[] vexs;  //顶点数组
 30     public int vexnum;  //顶点数
 31     public int arcnum;  //边数
 32     
 33     public Graph(int vexnum, int arcnum)
 34     {
 35         this.vexnum = vexnum;
 36         this.arcnum = arcnum;
 37         this.vexs = new VexNode[vexnum];
 38     }
 39     
 40     public void createUDG()
 41     {
 42         //1 创建顶点数组(顶点结点表)
 43         Scanner input = new Scanner(System.in);
 44         for(int i = 0; i < this.vexnum; i++)
 45             this.vexs[i] = new VexNode(input.next().charAt(0));
 46         
 47         //2 根据结点创建邻接表
 48         for(int k = 0; k < this.arcnum; k++)
 49         {
 50             char a = input.next().charAt(0);
 51             char b = input.next().charAt(0);
 52             int i = this.locateVex(a);
 53             int j = this.locateVex(b);
 54             ArcNode a1 = new ArcNode(j);
 55             //使用前插法插入边结点
 56             a1.nextarc = this.vexs[i].firstarc;
 57             this.vexs[i].firstarc = a1;
 58             ArcNode a2 = new ArcNode(i);
 59             a2.nextarc = this.vexs[j].firstarc;
 60             this.vexs[j].firstarc = a2;
 61         }
 62     }
 63     
 64     public int locateVex(char vex)
 65     {
 66         int i;
 67         for(i = 0; i < this.vexs.length && vex != this.vexs[i].data; i++);
 68         return i;
 69     }
 70 }
 71 
 72 //2 有向图的邻接表实现 时间复杂度: O(n+e) 空间复杂度: O(n+e)
 73 class ArcNode
 74 {
 75     //public int info;
 76     public int adjvex;
 77     public ArcNode nextarc;
 78     
 79     public ArcNode(int adjvex)
 80     {
 81         this.adjvex = adjvex;
 82         this.nextarc = null;
 83     }
 84 }
 85 
 86 class VexNode
 87 {
 88     public char data;
 89     public ArcNode firstarc;
 90     
 91     public VexNode(char data)
 92     {
 93         this.data = data;
 94         this.firstarc = null;
 95     }
 96 }
 97 
 98 class Graph  
 99 {
100     public VexNode[] vexs;
101     public int vexnum;
102     public int arcnum;
103     
104     public Graph(int vexnum, int arcnum)
105     {
106         this.arcnum = arcnum;
107         this.vexnum = vexnum;
108         this.vexs = new VexNode[vexnum];
109     }
110     
111     public void createDG()
112     {
113         Scanner input = new Scanner(System.in);
114         for(int i = 0; i < this.vexs.length; i++)
115             this.vexs[i] = new VexNode(input.next().charAt(0));
116         for(int k = 0; k < this.arcnum; k++)
117         {
118             char a = input.next().charAt(0);
119             char b = input.next().charAt(0);
120             int i = this.locateVex(a);
121             int j = this.locateVex(b);
122             ArcNode a1 = new ArcNode(j);
123             a1.nextarc = this.vexs[i].firstarc;
124             this.vexs[i].firstarc = a1;
125         }
126     }
127     
128     public int locateVex(char vex)
129     {
130         int i;
131         for(i = 0; i < this.vexs.length && vex != this.vexs[i].data; i++);
132         return i;
133     }
134 }

 

posted @ 2019-05-05 09:30  Huayra  阅读(1048)  评论(0编辑  收藏  举报