Codeforces 723C. Polycarp at the Radio 模拟
Polycarp is a music editor at the radio station. He received a playlist for tomorrow, that can be represented as a sequence a1, a2, ..., an, where ai is a band, which performs the i-th song. Polycarp likes bands with the numbers from 1 to m, but he doesn't really like others.
We define as bj the number of songs the group j is going to perform tomorrow. Polycarp wants to change the playlist in such a way that the minimum among the numbers b1, b2, ..., bm will be as large as possible.
Find this maximum possible value of the minimum among the bj (1 ≤ j ≤ m), and the minimum number of changes in the playlist Polycarp needs to make to achieve it. One change in the playlist is a replacement of the performer of the i-th song with any other group.
The first line of the input contains two integers n and m (1 ≤ m ≤ n ≤ 2000).
The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 109), where ai is the performer of the i-th song.
In the first line print two integers: the maximum possible value of the minimum among the bj (1 ≤ j ≤ m), where bj is the number of songs in the changed playlist performed by the j-th band, and the minimum number of changes in the playlist Polycarp needs to make.
In the second line print the changed playlist.
If there are multiple answers, print any of them.
4 2
1 2 3 2
2 1
1 2 1 2
7 3
1 3 2 2 2 2 1
2 1
1 3 3 2 2 2 1
4 4
1000000000 100 7 1000000000
1 4
1 2 3 4
In the first sample, after Polycarp's changes the first band performs two songs (b1 = 2), and the second band also performs two songs (b2 = 2). Thus, the minimum of these values equals to 2. It is impossible to achieve a higher minimum value by any changes in the playlist.
In the second sample, after Polycarp's changes the first band performs two songs (b1 = 2), the second band performs three songs (b2 = 3), and the third band also performs two songs (b3 = 2). Thus, the best minimum value is 2.
题目连接:http://codeforces.com/contest/723/problem/C
题意:改变播放清单里面的尽量少的播放歌曲,使得1~m播放次数最小的尽可能大。
思路:播放清单里面,1~m里面每首歌至少有播放n/m遍。
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#include<bits/stdc++.h> using namespace std; int a[3000]; int sign[3000],flag[3000]; int main() { int i,j,n,m; scanf("%d%d",&n,&m); for(i=1; i<=n; i++) { scanf("%d",&a[i]); if(a[i]<=m) sign[a[i]]++; } int cou=n/m,amount=n%m; int ans=0; for(i=1; i<=n; i++) { if(a[i]<=m&&sign[a[i]]<cou+1) continue; if(a[i]<=m&&sign[a[i]]==cou&&amount>=0) { if(flag[a[i]]==0) amount--; flag[a[i]]=1; continue; } for(j=1; j<=m; j++) if(sign[j]<cou) { if(a[i]<=m) sign[a[i]]--; sign[j]++; a[i]=j; ans++; break; } } cout<<cou<<" "<<ans<<endl; for(i=1; i<=n; i++) cout<<a[i]<<" "; cout<<endl; return 0; }