Connecting Graph

Given n nodes in a graph labeled from 1 to n. There is no edges in the graph at beginning.

You need to support the following method:
1. connect(a, b), add an edge to connect node a and node b. 2.query(a, b)`, check if two nodes are connected

Example

5 // n = 5
query(1, 2) return false
connect(1, 2)
query(1, 3) return false
connect(2, 4)
query(1, 4) return true

思路:考察图。定义root节点,从root节点入手,判断root节点是否相同,相同即存在连接关系。
public class ConnectingGraph { 
    private int[] father = null;
    public ConnectingGraph(int n) {
        // initialize your data structure here.
        father = new int[n + 1];
        for (int i = 1; i <= n; i++) {
            father[i] = i;
        }
    }

    public void connect(int a, int b) {
        // Write your code here
        int rootA = find(a);
        int rootB = find(b);
        if (rootA != rootB) {
            father[rootA] = rootB;
        }
    }
        
    public boolean  query(int a, int b) {
        // Write your code here
        int rootA = find(a);
        int rootB = find(b);
        return rootA == rootB;
        
    }
    
    private int find(int x) {
        if (father[x] == x) {
            return x;
        }
        return find(father[x]);
    }
}

 

posted @ 2017-07-16 19:59  YuriFLAG  阅读(128)  评论(0编辑  收藏  举报