C#启动另外一个程序
string exe_Path = "C:\\";//程序路径 System.Diagnostics.ProcessStartInfo info = new System.Diagnostics.ProcessStartInfo(); info.FileName = "xxx.exe"; info.WorkingDirectory = exe_Path; System.Diagnostics.Process proc; try { proc = System.Diagnostics.Process.Start(info); } catch (Exception ex) { MessageBox.Show(ex.Message); }