VMware Coding Challenge: The Heist

 1     static int maximize_loot(int[] gold, int[] silver) {
 2         int[][] res = new int[gold.length+silver.length+1][10001];
 3         res[0][0] = 0;
 4         for (int i=1; i<=gold.length; i++) {
 5             for (int j=0; j<=10000; j++) {
 6                 res[i][j] = Math.max(res[i-1][j], (j>=gold[i-1]? res[i-1][j-gold[i-1]]+10*gold[i-1] : 0));
 7             }
 8         }
 9         for (int i=1; i<=silver.length; i++) {
10             for (int j=0; j<=10000; j++) {
11                 res[i+gold.length][j] = Math.max(res[i+gold.length-1][j], (j>=silver[i-1]? res[i+gold.length-1][j-silver[i-1]]+1*silver[i-1] : 0));
12             }
13         }
14         int maxVal = 0;
15         for (int k=0; k<=10000; k++) {
16             maxVal = Math.max(maxVal, res[gold.length+silver.length][k]);
17         }
18         return maxVal;
19 
20     }

posted @ 2015-03-07 03:50 neverlandly 阅读(306) 评论(0) 编辑收藏举报

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