Lintcode: Fizz Buzz

Given number n. Print number from 1 to n. But:

when number is divided by 3, print fizz;

when number is divided by 5, print buzz;

when number is divided by both 3 and 5, print fizz buzz.

Example
If n=15, you should return ["1", "2", "fizz", "4", "buzz", "fizz", "7", "8", "fizz", "buzz", "11", "fizz", "13", "14", "fizz buzz"]

StringBuffer的用法，append方法的参数可以使boolean, char, char[], CharSequence, double, float, int, long, String, StringBuffer

 1 class Solution {
 2     /**
 3      * param n: As description.
 4      * return: A list of strings.
 5      */
 6     public ArrayList<String> fizzBuzz(int n) {
 7         ArrayList<String> res = new ArrayList<String>();
 8         for (int i=1; i<=n; i++) {
 9             StringBuffer buf = new StringBuffer();
10             if (i%3==0 && i%5!=0) {
11                 buf.append("fizz");
12             }
13             if (i%3!=0 && i%5==0) {
14                 buf.append("buzz");
15             }
16             if (i%3==0 && i%5==0) {
17                 buf.append("fizz buzz");
18             }
19             if (i%3!=0 && i%5!=0) {
20                 buf.append(i);
21             }
22             res.add(buf.toString());
23         }
24         return res;
25     }
26 }

Better way: http://www.cnblogs.com/EdwardLiu/p/6121453.html

posted @ 2015-02-07 03:22 neverlandly 阅读(725) 评论(0) 收藏举报

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