LeetCode 674. Longest Continuous Increasing Subsequence
原题链接在这里:https://leetcode.com/problems/longest-continuous-increasing-subsequence/
题目:
Given an unsorted array of integers, find the length of longest continuous
increasing subsequence.
Example 1:
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.
题解:
如果当前值比前个值大就count++, 更新res. 否则count清回1.
Time Complexity: O(num.length).
Space: O(1).
AC Java:
1 class Solution { 2 public int findLengthOfLCIS(int[] nums) { 3 if(nums == null || nums.length == 0){ 4 return 0; 5 } 6 7 int count = 1; 8 int res = 1; 9 for(int i = 1; i<nums.length; i++){ 10 if(nums[i] > nums[i-1]){ 11 count++; 12 res = Math.max(res, count); 13 }else{ 14 count = 1; 15 } 16 } 17 return res; 18 } 19 }