二进制练习小游戏

　　今天恶补汇编，发现脑袋变迟钝了，所以写了个小程序，练习一下二进制转换，巩固记忆~~

　　先来看看二进制（Binary）、十进制（Decimal）、十六进制（Hexadecimal）的关系表格

 

Decimal (base 10)	Binary (base 2)	Hexadecimal (base 16)
0	0000	0
1	0001	1
2	0010	2
3	0011	3
4	0100	4
5	0101	5
6	0110	6
7	0111	7
8	1000	8
9	1001	9
10	1010	A
11	1011	B
12	1100	C
13	1101	D
14	1110	E
15	1111	F

　　根据对应关系，写了如下小代码，亦可以统计成功率

　　

#include <iostream>
#include <ctime>
#include <cstdlib>
#include <string>
#include <bitset>
#include <iomanip>

using namespace std;

int main(int argc, char *argv[])
{
    cout << "You must enter a 4-digit binary number." << endl;
    cout << "If you enter 'q' or 'Q', then the game over~"<< endl;
    cout << "Now, let's start the game!" << endl;
    cout << endl;

    unsigned long correctCount = 0;
    unsigned long totalCount = 0;
    srand(time(NULL));
    do{
        unsigned long v = rand() % 16;
        if(0 == (rand() - (v >> 1)) % 2){
            cout << "0x" << hex << uppercase << v << " = " << resetiosflags(ios_base::hex | ios_base::uppercase);
        }else{
            cout << v << " = ";
        }

        string str;
        cin >> str;

        if(0 == str.compare("q") || 0 == str.compare("Q")){
            cout << endl;
            break;
        }

        if(str.size() > 4){
            cout << "Please enter a valid 4-digit binary number" << endl;
        }else{
            try{
                bitset<4> foo(str);

                totalCount++;
                if(foo.to_ulong() == v){
                        correctCount++;
                    cout << "^_-! Bingo!" << endl;
                }else
                    cout << "-_-! Once again!" << endl;
            }catch(...){
                cout << "Please enter the binary format!" << endl;
            }
        }

        cout << endl;
    }while(1);

    if(totalCount > 0)
        cout << "Correct Rate: " << correctCount / double(totalCount) * 100 << "%" << endl;

    cout << "Bye-bye ^_^!" << endl;
    return 0;
}