LeetCode(15)3Sum

题目如下:

Python代码:

def threeSum(self, nums):
        res = []
        nums.sort()
        for i in xrange(len(nums)-2):
            if i > 0 and nums[i] == nums[i-1]:
                continue
            l, r = i+1, len(nums)-1
            while l < r:
                s = nums[i] + nums[l] + nums[r]
                if s < 0:
                    l +=1 
                elif s > 0:
                    r -= 1
                else:
                    res.append((nums[i], nums[l], nums[r]))
                    while l < r and nums[l] == nums[l+1]:
                        l += 1
                    while l < r and nums[r] == nums[r-1]:
                        r -= 1
                    l += 1; r -= 1
        return res

 

posted @ 2017-07-14 15:29  Single、Dog  阅读(158)  评论(0编辑  收藏  举报