情人节送ta一朵独一无二的玫瑰花

完成源码(开发版)

<!DOCTYPE HTML>

<html> 

<head> 

<title>Rose</title> 

<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> 

</head> 

<body style="margin-left:200px"> 

<div style="text-align: center">

    <canvas id="c"></canvas>

</div>

 

<script type="text/javascript">

    var canvas = document.getElementsByTagName('canvas')[0];

    var context = canvas.getContext('2d');

 

    var a = context;

    var b = document.body;

    var c = canvas;

 

    document.body.clientWidth;

    var zBuffer = [];

    var SIZE = 777;

    canvas.width = canvas.height = SIZE;

    var h = -350;

 

    function surface(a, b, c) { 

        if (c > 60) { 

            return {  

                x : Math.sin(a * 7) * (13 + 5 / (.2 + Math.pow(b * 4, 4)))  - Math.sin(b) * 50, 

                y : b * SIZE + 50,  

                z : 625 + Math.cos(a * 7)   * (13 + 5 / (.2 + Math.pow(b * 4, 4))) + b * 400, 

                r : a * 1 - b / 2,  g : a  }; 

            }

 

        var A = a * 2 - 1;

        var B = b * 2 - 1;

 

        if (A * A + B * B < 1) {

        if (c > 37) {

            var j = c & 1; 

            var n = j ? 6 : 4;  

            var o = .5 / (a + .01) + Math.cos(b * 125) * 3 - a * 300; 

            var w = b * h; 

            return {  

                x : o * Math.cos(n) + w * Math.sin(n) + j * 610 - 390, 

                y : o * Math.sin(n) - w * Math.cos(n) + 550 - j * 350, 

                z : 1180 + Math.cos(B + A) * 99 - j * 300, 

                r : .4  - a  * .1   + Math.pow(1 - B * B, -h * 6)  * .15  - a  * b  * .4   + Math.cos(a + b)  / 5   + Math.pow(Math.cos((o * (a + 1) + (B > 0 ? w  : -w)) / 25), 30) * .1 * (1 - B * B),  g : o / 1e3 + .7 - o * w * 3e-6

            }; 

        }

 

        if (c > 32) { 

            c = c * 1.16 - .15; 

            var o = a * 45 - 20; 

            var w = b * b * h; 

            var z = o * Math.sin(c) + w * Math.cos(c) + 620; 

            return { 

                x : o * Math.cos(c) - w * Math.sin(c), 

                y : 28 + Math.cos(B * .5) * 99 - b * b * b * 60 - z / 2  - h, 

                z : z, 

                r : (b * b * .3 + Math.pow((1 - (A * A)), 7) * .15 + .3)  * b, 

                g : b * .7 

            }; 

        }

 

        var o = A * (2 - b) * (80 - c * 2); 

        var w = 99 - Math.cos(A) * 120 - Math.cos(b) * (-h - c * 4.9)  + Math.cos(Math.pow(1 - b, 7)) * 50 + c * 2; 

        var z = o * Math.sin(c) + w * Math.cos(c) + 700; 

        return { 

            x : o * Math.cos(c) - w * Math.sin(c), 

            y : B * 99 - Math.cos(Math.pow(b, 7)) * 50 - c / 3 - z  / 1.35 + 450,  z : z, 

            r : (1 - b / 1.2) * .9 + a * .1, 

            g : Math.pow((1 - b), 20) / 4 + .05 

        }; 

        } 

    }  

 

 

 

    setInterval(function() { 

        for ( var i = 0; i < 10000; i++) {  

            var part = i % 46;  

            var c = part / .74;  

            var point = surface(Math.random(), Math.random(), c); 

            if (point) { 

                var z = point.z; 

                var x = parseInt(point.x * SIZE / z - h); 

                var y = parseInt(point.y * SIZE / z - h); 

                var zBufferIndex = y * SIZE + x; 

                if ((typeof zBuffer[zBufferIndex] === "undefined")  || (zBuffer[zBufferIndex] > z)) { 

                    zBuffer[zBufferIndex] = z;  

                    var r = -parseInt(point.r * h);  var g = -parseInt(point.g * h); 

                    var b = -parseInt(point.r * point.r * -80);  

                    context.fillStyle = "rgb(" + r + "," + g + "," + b  + ")"; 

                    context.fillRect(x, y, 1, 1); 

                } 

            } 

        } 

    }, 0); 

 

</script>

 

</body> 

</html>

情人节这么浪漫的告白,快去试试吧,送她或者他一朵与众不同的玫瑰花

posted @ 2017-02-12 11:00  CC大神01  阅读(374)  评论(0编辑  收藏  举报