10051

还是普通动规的思路,只不过注意一点,上面那个的下面和下面那个的上面是相同的,要处理一下。

//============================================================================
// Name        : 10051.cpp
// Author      : 
// Version     :
// Copyright   : Your copyright notice
// Description : Hello World in C++, Ansi-style
//============================================================================

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;



typedef struct{
	int x, y;
}block;

block pre[600][10], next[600][10], Max;
int maxnum;
int n, t1, t2, m1, m2, t;
int a[600][10], d[600][10];
char s[7][10] = {"", "front", "back", "left", "right", "top", "bottom"};



int main() {
	freopen("a.txt", "r", stdin);
	int T = 0;
	while(scanf("%d", &n)&&n){
		T++;
		if(T!=1){
			printf("\n");
		}
		printf("Case #%d\n", T);
		for(int i = 1;i <= n;i++){
			for(int j = 1;j <= 6;j++){
				scanf("%d", &a[i][j]);
				d[i][j] = 1;
			}
		}
		maxnum = 1;
		Max.x = 1;
		Max.y = 1;
		for(int i1 = 2;i1 <= n;i1++){
			for(int i2 = 1;i2 <= 6;i2++){
				for(int j = 1;j < i1;j++){
					for(int k = 1;k <= 6;k++){
						t = k;
						if(k%2){
							t = t+1;
						}
						else{
							t = t-1;
						}
						if(a[i1][i2] == a[j][t]){
							if(d[i1][i2] < d[j][k]+1){
								d[i1][i2] = d[j][k]+1;
								pre[i1][i2].x = j;
								pre[i1][i2].y = k;
								if(maxnum < d[i1][i2]){
									maxnum = d[i1][i2];
									Max.x = i1;
									Max.y = i2;
								}
							}
						}
					}
				}
			}
		}
		printf("%d\n", maxnum);
		if(maxnum == 1){
			printf("1 ");
			printf("%s\n", s[1]);
		}
		else{
			t1 = Max.x;
			t2 = Max.y;
//			printf("%d %d\n", t1, t2);
			while(d[t1][t2]!=1){
				m1 = pre[t1][t2].x;
				m2 = pre[t1][t2].y;
				next[m1][m2].x = t1;
				next[m1][m2].y = t2;
				t1 = m1;
				t2 = m2;
//				printf("%d %d\n", t1, t2);
			}
			printf("%d ", t1);
			printf("%s\n", s[t2]);
//			printf("\n");
//			printf("%d %d\n", t1, t2);
			while(t1!=Max.x){
				m1 = next[t1][t2].x;
				m2 = next[t1][t2].y;
				t1 = m1;
				t2 = m2;
//				printf("%d %d\n", t1, t2);
				printf("%d ", t1);
				printf("%s\n", s[t2]);
			}
		}
	}
	return 0;
}

  

posted @ 2011-07-29 10:21  KOKO's  阅读(472)  评论(0编辑  收藏  举报