hdu 1052 贪心

// 判断出（田忌）的必胜局面和必败局面，则可以容易的得到决策方案

// 若没有明显的必胜局面和必败局面，则使用田忌赛马的策略

 1 #include "bits/stdc++.h"
 2 using namespace std;
 3 int N;
 4 int v1[1010], v2[1010];
 5 
 6 int main()
 7 {
 8     while(scanf("%d", &N) && N) {
 9         int i, j;
10         for(i = 1; i <= N; ++i) {
11             scanf("%d", &v1[i]);
12         }
13         sort(v1 + 1, v1 + 1 + N);
14         for(j = 1; j <= N; ++j) {
15             scanf("%d", &v2[j]);
16         }
17         sort(v2 + 1, v2 + 1 + N);
18 
19         int l1, r1, l2, r2;
20         l1 = l2 = 1;
21         r1 = r2 = N;
22         int win_time, lost_time;
23         win_time = lost_time = 0;
24 
25         while(l1 <= r1) {
26 //            printf("l1 == %d   r1 == %d   l2 == %d   r2 == %d  win_time == %d  lost_time == %d\n", l1, r1, l2, r2, win_time, lost_time);
27             if(v1[l1] > v2[l2]) {
28                 ++win_time;
29                 ++l1;
30                 ++l2;
31                 continue;
32             }
33             if(v1[l1] < v2[l2]) {
34                 ++lost_time;
35                 ++l1;
36                 --r2;
37                 continue;
38             }
39             if(v1[r1] > v2[r2]) {
40                 ++win_time;
41                 --r1;
42                 --r2;
43                 continue;
44             }
45             if(v1[r1] < v2[r2]) {
46                 ++lost_time;
47                 ++l1;
48                 --r2;
49                 continue;
50             }
51 
52             if(v1[l1] == v2[r2]) {
53                 ++l1;
54                 --r2;
55                 continue;
56             }
57             if(v1[l1] < v2[r2]) {
58                 ++lost_time;
59                 ++l1;
60                 --r2;
61                 continue;
62             }
63         }
64         printf("%d\n", (win_time - lost_time) * 200);
65     }
66 }

 

posted @ 2015-07-17 16:46  AC_Phoenix  阅读(148)  评论(0)  编辑  收藏  举报