解决远控重复上线的源码

View Code
1 nCnt = m_serverlist.GetItemCount(); //获得当前在线的主机数量
2 nItem=m_serverlist.InsertItem(nCnt,(_bstr_t)ip,0); //nItem=新增加的记录,nItem值由自动排序生成,所以数值不会顺序生成
3
4 if(nCnt>1) //最后一项要大于1
5 {
6 --nCnt;
7 int i2=1;
8 //for(Tmpi=nItem;Tmpi<++nItem;Tmpi++ )
9 //{//nItem值是随机的,主机上线会自动按IP地址对nItem进行排序
10 //先判断外网IP和主机名称:
11 //Tmpi=nItem+1;
12 for(Tmpi=nItem+1;Tmpi<nItem+3;Tmpi++ )
13 {
14 if(m_serverlist.GetItemText(nItem,0 ) == m_serverlist.GetItemText(Tmpi,0)&&m_serverlist.GetItemText(nItem,1) == m_serverlist.GetItemText(Tmpi,1))
15 //if(m_serverlist.GetItemText(nItem,0 ) == m_serverlist.GetItemText(Tmpi,0))
16 {
17 //MessageBox("Host online repeat!","WARN");
18 // MessageBox(m_serverlist.GetItemText(Tmpi,0));
19
20 m_serverlist.DeleteItem(Tmpi); //删除以前的重复IP地址,保留最新的连接
21
22 }
23 //--Online;
24 nCnt = m_serverlist.GetItemCount();
25 temp.Format("Current Online: %d hosts",nCnt);
26 AfxGetMainWnd()->SetDlgItemText(IDC_STATIC_1, temp);
27 m_serverlist.Update(0);
28 }
posted @ 2011-06-07 11:22  星星的学习小志  阅读(429)  评论(0编辑  收藏  举报