PAT-1097(Depulication on a Linked List)

  题目见这里

   分析:实际上是静态链表的应用,只不过要删除的结点链接成一个新的Removed List

//静态链表
#include <stdio.h> 
#define KEYMAX 10005
#define MAXADDRESS 100005

typedef struct{
	int data; 
	int next; //下一个元素的下标 
}SLinkList;

int n,kHead,rHead;
SLinkList sLinkList[MAXADDRESS];
int flag[KEYMAX];

int Transform(char *address){
	if(address[0]=='-') return -1;//仅-1为负数
	int p,i;
	p=0,i=0;
	while(address[i]){
		p = 10*p+address[i]-'0';
		i ++;
	}
	return p;
}

void Read(){
	char address[6],next[6];
	int data,p;
	scanf("%s%d",address,&n);
	getchar();
	kHead = Transform(address);
	while(n--){
		scanf("%s%d%s",address,&data,next);
		p = Transform(address);
		sLinkList[p].data = data;
		sLinkList[p].next = Transform(next);
	}
}

void DeDuplication(){
	int prior,next,q,data,i=1;
	prior = next = kHead;
	while(next!=-1){
		data = sLinkList[next].data;
		if(data<0) data = -data;
		if(flag[data]){
			//删除结点 
			sLinkList[prior].next = sLinkList[next].next;
			if(i==1){
				rHead = next;
				q = rHead;
				sLinkList[q].next = -1;
				i ++;
			}
			else{
				sLinkList[q].next = next;
				sLinkList[next].next = -1;
				q = next;
			}
			//next结点链接到rHead所在链表之后再更新next 
			next = sLinkList[prior].next; 
		}
		else{
			flag[data] = 1;
			prior = next;
			next = sLinkList[next].next;
		}
	}
}

void OutPut(int head){
	int p = head;
	if(p==-1) return; //removed list可能为空 
	do{
		printf("%05d %d ",p,sLinkList[p].data);
		if(sLinkList[p].next!=-1)
			printf("%05d\n",sLinkList[p].next);
		else printf("-1\n");  
		p = sLinkList[p].next;
	}while(p!=-1);
}

int main(){
//	freopen("Data.txt","r",stdin); 
	kHead = rHead = -1;
	Read();
//	OutPut(kHead);
//	puts("~~~分界线~~~");
	DeDuplication();
	OutPut(kHead);
	OutPut(rHead);
	return 0;
}

 

 

posted @ 2017-07-07 16:10  我在这儿  阅读(322)  评论(0编辑  收藏  举报