STL_A1100 Mars Numbers (20 分)

https://pintia.cn/problem-sets/994805342720868352/problems/994805367156883456

/*
*map的使用
*预处理数据,即打表init()
*字符串输入getline(cin,str);
*/
#include<iostream> using namespace std; #include<cstdio> #include<string> #include<map> string unitDigit[13]={"tret","jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"}; string higherDigit[13]={"tret","tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"}; string earthToMars[170]; map<string,int> marsToEarth; void init() { //打表? for(int i=0;i<13;i++) { earthToMars[i]=unitDigit[i]; marsToEarth[unitDigit[i]]=i; earthToMars[i*13]=higherDigit[i]; marsToEarth[higherDigit[i]]=i*13; } for(int i=1;i<13;i++) { for(int j=1;j<13;j++) { string str=higherDigit[i]+" "+unitDigit[j]; //注意i,j earthToMars[i*13+j]=str; marsToEarth[str]=i*13+j; } } }
int main() { init(); //打表 int n; scanf("%d",&n); getchar(); //吸收空格 while(n--) { //用while循环n次 string str; getline(cin,str); //输入字符串 if(str[0]>='0'&&str[0]<='9') { //如果是数字 //把数字字符转换为十进制数 int num=0; for(int i=0;i<str.length();i++) { num=num*10+(str[i]-'0'); } cout<<earthToMars[num]<<endl; }else { cout<<marsToEarth[str]<<endl; } } return 0; }
posted @ 2019-08-16 22:45  2o2o  阅读(117)  评论(0编辑  收藏  举报