Python 列表魔法三

v = "alex"
v = v.replace("l","el")
print(v)

 

 

 


li = [11,22,33,44,55]
li[0] = 00
print(li)

 

 

 



#补充:错误,字符串创建后不可更改
li ="alex"
li[0]
li[0] = "E"

 

posted @ 2019-09-24 21:22  别看我看路  阅读(127)  评论(0编辑  收藏  举报